C语言实现的程序员老黄历实例

本文实例讲述了C语言实现的程序员老黄历。分享给大家供大家参考。具体如下：

以前看到过一个jquery程序员老黄历页面，觉得挺有创意的，自己闲着用C语言也写了一个，基本就是随机数的生成，没什么难度，大家随便看看，高手请绕过此篇，控制台程序没什么美观可言，已经尽量弄得好看点了。

#include <stdio.h>

#include <time.h>

int random(int dayseed,int indexseed)

//根据当前时间“天 ”产生伪随机数。

{

int i,n;

n = dayseed % 11117;

for (i = 0; i < 100 + indexseed; i++)

{

n = n * n;

n = n % 11117; // 11117 是个质数

}

return n;

}

int isWeekend(struct tm *p)

{

return p->tm_wday == 0 || p->tm_wday == 6;

}

int main(int argc, char *argv[])

{

char *weeks[6] = {"一","二","三","四","五","六","日"};

printf("|-------------------------------------|n");

printf("| 程序员老黄历beta 1.0 |n");

printf("|-------------------------------------|n");

time_t timep;

struct tm *p;

time(&timep);

p =localtime(&timep);

//此函数获得的tm结构体的时间，是已经进行过时区转化为本地时间

printf("|-------------------------------------|n");

printf("| 今天是%d年%d月%d日 星期%s |n",1900+p->tm_year,1+p->tm_mon,p->tm_mday,weeks[p->tm_wday-1]);

printf("|-------------------------------------|n");

int randNum=random(p->tm_mday, 2);//产生伪随机数

int randNum1=random(p->tm_mday, 3);

char *activities[27][3] = {

{"写单元测试", "写单元测试将减少出错","写单元测试会降低你的开发效率"},

{"白天上线", "今天白天上线是安全的","可能导致灾难性后果"},

{"重构", "代码质量得到提高","你很有可能会陷入泥潭"},

{"使用%t", "你看起来更有品位","别人会觉得你在装逼"},

{"跳槽", "该放手时就放手","鉴于当前的经济形势，你的下一份工作未必比现在强"},

{"招人", "你遇到千里马的可能性大大增加","你只会招到一两个混饭吃的外行"},

{"面试", "面试官今天心情很好","面试官不爽，会拿你出气"},

{"提交辞职申请", "公司找到了一个比你更能干更便宜的家伙，巴不得你赶快滚蛋","鉴于当前的经济形势，你的下一份工作未必比现在强"},

{"申请加薪", "老板今天心情很好","公司正在考虑裁员"},

{"晚上加班", "晚上是程序员精神最好的时候","", },

{"命名变量"%v"", "",""},

{"写超过%l行的方法", "你的代码组织的很好，长一点没关系","你的代码将混乱不堪，你自己都看不懂"},

{"提交代码", "遇到冲突的几率是最低的","你遇到的一大堆冲突会让你觉得自己是不是时间穿越了"},

{"代码复审", "发现重要问题的几率大大增加","你什么问题都发现不了，白白浪费时间"},

{"开会", "写代码之余放松一下打个盹，有益健康","你会被扣屎盆子背黑锅"},

{"晚上上线", "晚上是程序员精神最好的时候","你白天已经筋疲力尽了"},

{"修复BUG", "你今天对BUG的嗅觉大大提高","新产生的BUG将比修复的更多"},

{"设计评审", "设计评审会议将变成头脑风暴","人人筋疲力尽，评审就这么过了"},

{"需求评审", "",""},

{"打DOTA", "你将有如神助","你会被虐的很惨", }, //这里往下的是周末特定情况 （19-27）

{"洗澡", "你几天没洗澡了？","会把设计方面的灵感洗掉", },

{"锻炼一下身体", "","能量没消耗多少，吃得却更多", },

{"抽烟", "抽烟有利于提神，增加思维敏捷","除非你活够了，死得早点没关系", },

{"在妹子面前吹牛", "改善你矮穷挫的形象","会被识破", },

{"撸管", "避免缓冲区溢出","强撸灰飞烟灭", },

{"浏览成人网站", "重拾对生活的信心","你会心神不宁", },

{"上微博", "今天发生的事不能错过","会看到令人心情不好的事", },

{"上AB站", "还需要理由吗？","满屏的兄贵我会说出来？", }

};

printf("|-------------------------------------|n");

if(isWeekend(p))

printf("| 宜: n| %2sn| %sn",activities[19+randNum%8][0],activities[randNum%27][1]);

else

printf("| 宜: n| %2sn| %sn",activities[randNum%17][0],activities[randNum%27][1]);

printf("|-------------------------------------|n");

printf("|-------------------------------------|n");

if(isWeekend(p))

printf("| 不宜:n| %sn| %sn",activities[19+randNum1%8][0],activities[randNum1%27][2]);

else

printf("| 不宜:n| %sn| %sn",activities[randNum1%17][0],activities[randNum1%27][2]);

printf("|-------------------------------------|n");

/*座位朝向*/

char *directions[8]= {"北方","东北方","东方","东南方","南方","西南方","西方","西北方"};

printf("|-------------------------------------|n");

printf("| 座位朝向：面向 %s 写程序，BUG 最少.n",directions[randNum%8]);

/*今日宜饮*/

char *drinks[14] = {"水","茶","红茶","绿茶","咖啡","奶茶","可乐","牛奶","豆奶","果汁","果味汽水","苏打水","运动饮料","酸奶","酒"};

printf("|-------------------------------------|n");

printf("| 今日宜饮:%s,%sn",drinks[randNum%14],drinks[randNum1%14]);

/*女神亲近指数*/

int ambiguous = randNum%10;

printf("|-------------------------------------|n");

if(10==ambiguous)

printf("| 亲近指数为10，上吧，骚年！n");

else

printf("| 女神亲近指数:%d n",ambiguous);

printf("|-------------------------------------|n");

return 0;

}

运行效果如下图所示：