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Linux下php5.4启动脚本

2014-08-06 21:00作者:zhao

对于linux系统我想大家都不会很陌生,全英文的界面,操作起来很是方便,占用资源也是少之又少,不仅仅是这些吸引了我们,而是他的操作起来的千变万化,可以承载很多意想不到的东西,在这里我给大家讲下如何在linux下设置php的启动脚本。

废话不多说,直接上步骤

1、修改php-fpm.conf配置文件

修改/usr/local/php/etc/php-fpm.conf(当然这个跟你配置的php路径相关)配置文件

 

启动pid=run/php-fpm.pid

; Pid file

; Note: the default prefix is /usr/local/php/var

; Default Value: none

pid = run/php-fpm.pid

启动error_log=log/php-fpm.log

; Error log file

; If it's set to "syslog", log is sent to syslogd instead of being written

; in a local file.

; Note: the default prefix is /usr/local/php/var

; Default Value: log/php-fpm.log

error_log = log/php-fpm.log

如果不知道怎么修改它们那你们先看下linux的vi  编辑器 是怎么操作的,启动那个就把前面的“;”去掉就好了

2、创建/etc/init.d/php文件
root@admin5:~# cat /etc/init.d/php
#!/bin/bash
#Author:zhao
#E-mail:admin5#admin5.com
#Website:http://down.admin5.com

# pid file
pid="/usr/local/php/var/run/php-fpm.pid"
# php-fpm path&file
phpfpm="/usr/local/php/sbin/php-fpm"

param=$1

phpnum=`ps -ef | grep php-fpm | wc -l`

if [ "$param" = "stop" ]; then
if [ "$phpnum" = "1" ]; then
echo "Php process does not exist."
exit 1
fi
kill `cat $pid`
echo "Close php processes. OK"
exit 1
fi

if [ "$param" = "start" ]; then
if [ "$phpnum" != "1" ]; then
echo "Php process exist."
exit 1
fi
$phpfpm
echo "Open php processes. OK"
exit 1
fi

if [ "$param" = "restart" ]; then
if [ "$phpnum" = "1" ]; then
echo "Php process does not exist. Stop Failed."
else
kill `cat $pid`
for i in `ps -ef | grep php-fpm | grep -v grep | awk {'print $2'}`
do
kill -9 $i
echo "Kill $i successed."
done
echo "Close php processes. OK"
fi
$phpfpm
if [ "$phpnum" != "1" ]; then
echo "Open php processes. OK"
else
echo "Open php processes. Failed."
fi
exit 1
fi
3、修改权限

root@admin5:~#chmod +x /etc/init.d/php

4、执行结果

执行结果

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