A5下载文章资讯

分类分类

JavaScript使用RegExp进行正则匹配的方法

2015-07-11 11:24作者:zhao

本文实例讲述了JavaScript使用RegExp进行正则匹配的方法。分享给大家供大家参考。具体实现方法如下:

<script type="text/javascript">

var matchedTimes = 0;

//Match one d followed by one or more b's followed by one d

//Remember matched b's and the following d

//Ignore case

myRe = new RegExp("d(b+)(d)", "ig");

// 等价于 myReg = /d(b+)(d)/ig;

myArray = myRe.exec("ecDBDsdbbdz"); // ecdbBdbsdbbdz

console.log("Regular Expression String: " + myRe.source);

console.log("Is global? " + myRe.global);

console.log("Ignore case? " + myRe.ignoreCase);

console.log("Is mulitiline? " + myRe.multiline);

console.log("------------------------------------------------");

logInfo(myArray, myRe);

myArray = myRe.exec("ecDBDsdbbdz");

logInfo(myArray, myRe);

function logInfo(myArray, myRe) {

matchedTimes++;

console.log("This is " + matchedTimes + " times match");

console.log("Original String: " + myArray.input);

console.log("Match Result Array: [" + myArray + "]");

console.log("The 0-based index of the match in the string: " + myArray.index);

console.log("The last matched characters: " + myArray[0]);

console.log("The parenthesized substring matches [1]: " + myArray[1]);

console.log("The parenthesized substring matches [2]: " + myArray[2]);

console.log("The index at which to start the next match: " + myRe.lastIndex);

console.log("-----------------------------------------------");

}

myRe2 = /^w+(d*)$/ig

console.log("myRe2: " + myRe2.source);

//console.log("myRe2 matches abc1? " + myRe2.test("abc1"));

// 加上这行跑跑看结果,因为是global匹配,所以lastIndex会改变,

//所以后面的myRe2.test("abc")当然就是false

console.log("myRe2 matches abc? " + myRe2.test("abc"));

</script>

希望本文所述对大家的javascript程序设计有所帮助。

展开全部

相关

说两句网友评论
    我要跟贴
    取消